pears problem

Let the number of pears sold in the morning be $x$ and those sold in the afternoon be $y$ .
$\begin{aligned} y & = 2x\\ 2x - y& = 0 \longrightarrow \boxed{1}\\ \\ x + y & = 360 \longrightarrow \boxed{2}\\ \\ \text{Adding}\boxed{1}\text{and}\boxed{2}:-\\ 3x & = 360\\ x & = \dfrac{360}{3}\\ & = 120\\ \\ \text{Substituting x = 120 in}\boxed{2}:-\\ 120 + y & = 360\\ y & = 360 - 120\\ & = \color{#69047E}{\boxed{240}} \end{aligned}$

Call the amount of pears sold in the morning is $x$ . $\implies$ The amount of pears sold in the afternoon is $2x$ . So $360=2x+x=3x(kg)$ $\implies 2x=3x \times \frac{2}{3}=360 \times \frac{2}{3}=360 \times 2/3=720/3=\boxed{240}$