An algebra problem by Madhavarapu Revanth
Algebra
Level
pending
a^1/x=b^1/y=c^1/z if a,b,c are in G.P then x,y,z will be in
H.P
A.P
G.P
none
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1 solution
Given that a^1/x=b^1/y=c^1/z. Let a^1/x=k then a=k^x. Like wise b=k^y and c=k^z. Given a,b,c are in G.P then a^2=bc. Therefore k^2y=k^x.k^z. k^2y=k^x+z, 2y=x+z
Therefore x,y,z are in A.P