The length of rectangle R is 10% more than the side of square S. The width of the rectangle is 10 % less than the side of the square. The ratio of the areas, R : S, is
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S = a 2
where: a : side of the square
R = L ∗ W
where:
L : length of the Rectangle
W : Width of the Rectangle
given that:
L = 1 1 0 % a = 1 . 1 a
W = 9 0 % a = 0 . 9 a
then
R = 1 . 1 a × 0 . 9 a = 0 . 9 9 a 2
R : S = 9 9 : 1 0 0
Just assume a length and breath rectangle.I assumed length and breath both 10. Its area will be 10x10=100 . After this length became 11 and breath became 9 . So the area of new triangle will be 11x9=99. So ratio is 99:100.
Taking 10% more length of rectangle and width 10 % less, considering 10 as length and width of square,areas are 99 and 100 ,so ,ratio of R:S is 99/100 Ans.
K.K.GARG,India
Let, the side of the square is y. So, length and width of the rectangle is 1.1y and 0.9y respectively. Hence, the ratio is (1.1y)(0.9y) : y.y i.e. 99:100
hmm its easy now
Guess the side of the square is 100. So he rectangular has 110 height and 90 wight. Area of R=110 90=9900 & S=100 100=10000. So R:S=9900/10000=99:100
Let x the side of square. Then, we have the sides of rectangle 1,1x and 0,9x. So, the ratio of the areas R/S = 1,1*0,9 * x²/x² = 0,99 = 99/100
If side of a square=x, then Rectangle's Length= 1.1x , Width=0.9x
So Area of Rectangle/Area of Square =(1.1x*0.9x)/x^2 =0.99=99/100
area of square = S^2 area of rectangle = 1.1S x 0.9S = 0.99(S^2) Ratio = (0.99(S^2)) : (S^2) = 99 : 100
If a be the side of a square then the length of the rectangle is 11/10 a and width of rectangle is 9/10 a. Area of the rectangle is 99/100 a a and area of the square is a^2. Therefore the ratio of r/s is 99/100.
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Let the side of the square be x,
It is given that,
Length of Rectangle R = x + 10/100 * x
Width of Rectangle R = x - 10/ 100 * x
from (1) and (2)
Ar R = L * W = 110x/100 * 90x/ 100
Ar S = x^2
R : S =R/s = 99x^2/100 / x^2
It's Easy.