An algebra problem by A Former Brilliant Member

Algebra Level 2

Find the sum of all numbers from 1 to 100000 that are divisible by 124.


Try some of my problems: Math Problems - Set 1


The answer is 40327404.

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1 solution

The series of numbers forms an Arithmetic Progression with a 1 = 124 a_1=124 , a 2 = 248 a_2=248 , and so on. To find the number of terms, we need to divide 100000 by 124 and it is 806.45. We consider only the whole number, so n = 806 n=806 . The last term is ( 806 ) ( 124 ) = 99944 (806)(124)=99944

S = S= n 2 ( a 1 + a n ) \frac{n}{2}(a_1+a_n)

S = S= 806 2 ( 124 + 99944 ) = 40327404 \frac{806}{2}(124+99944)=40327404

This is a very good question.

A Former Brilliant Member - 3 years, 7 months ago

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