Find the sum of all numbers from 1 to 100000 that are divisible by 124.
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The series of numbers forms an Arithmetic Progression with a 1 = 1 2 4 , a 2 = 2 4 8 , and so on. To find the number of terms, we need to divide 100000 by 124 and it is 806.45. We consider only the whole number, so n = 8 0 6 . The last term is ( 8 0 6 ) ( 1 2 4 ) = 9 9 9 4 4
S = 2 n ( a 1 + a n )
S = 2 8 0 6 ( 1 2 4 + 9 9 9 4 4 ) = 4 0 3 2 7 4 0 4