An algebra problem by Mateo Matijasevick

Algebra Level 2

20160 2016 2016000 201600 × 2000 + 16 = ? \large \sqrt { \dfrac { 20160-2016 }{ 2016000-201600 } \times 2000+16 }= \, ?


The answer is 6.

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1 solution

20160 2016 2016000 201600 × 2000 + 16 = 2016 ( 10 1 ) 2016 ( 1000 100 ) × 2000 + 16 = 9 900 × 2000 + 16 = 20 + 16 = 6 \sqrt { \frac { 20160-2016 }{ 2016000-201600 } \times 2000+16 }=\sqrt { \frac { 2016(10-1) }{ 2016(1000-100) } \times 2000+16 } =\sqrt { \frac { 9 }{ 900 } \times 2000+16 } =\sqrt { 20+16 } =6

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