The sum of first 12 terms of an arithmetic progression is 144, and the sum of the first 20 terms of the same progression is 560.
What is the sum of first 6 terms of this same progression?
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Let first term = a , common difference = d
144 = 6(2a + 11d) , 560 = 10(2a + 19d)
a = -10 , d = 4 ---> sum of first 6 terms = 3(2×(-10) + 5×4) = 0