An algebra problem by Mohammad Khaza

Given that,

• $x = 1$

Now,

$= (1 + 1)^{10}$

$\Rightarrow 2^{10} = 1024$

For $4^5$

$\Rightarrow 4^5 = 4 \times 4 \times 4 \times 4 \times 4 =1024$

x=1 . so. (x + 1/x) =2

so, (x + 1/x )^10= 2^10 = 2^( 2 . 5) = 4^5

$x = 1$

$={ \left( x+\frac { 1 }{ x } \right) }^{ 10 }\\ ={ \left( 1+\frac { 1 }{ 1 } \right) }^{ 10 }\\ ={ 2 }^{ 10 }\\ ={ 4 }^{ 5 }$ .

If ${x} = {1}$ , then we have ${{2}^{10}} = {1024}$ .

$4^{5} = (2^{2})^{5} = 2^{10}$ .

So, the answer is ${4}^{5}$ .