A geometry problem by Neil Cua

Geometry Level 1

The perimeter of an isoceles triangle measures 29 in. One side of the triangle is 5 in. longer than each of the 2 equal sides. Find the length of the longer side of the triangle.

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Neil Cua by Neil Cua , 20, Philippines

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1 solution

Rakshit Pandey
Aug 1, 2014

Let the sides of the isosceles triangle be a a , a a & ( a + 5 ) (a+5) .
Perimeter of a Polygon= Sum of all the sides
So,
29 = a + a + ( a + 5 ) 29=a+a+(a+5)
⇒ 29 = 3 a + 5 \Rightarrow 29=3a+5
⇒ a = 29 − 5 3 \Rightarrow a=\frac{29-5}{3}
⇒ a = 24 3 \Rightarrow a=\frac{24}{3}
⇒ a = 8 i n \Rightarrow \boxed{a= 8in}
So, Larger side= ( a + 5 ) = 8 + 5 = 13 i n (a+5)=8+5=\boxed{13in}

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