An algebra problem by Parth Bhardwaj

Algebra Level 3

lets take j as a hidden number. then find the value of (a-j)(b-j)(c-j)(d-j)...................(y-j)(z-j)+j

Infinite not defined j 0

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Sanjeet Raria
Oct 11, 2014

There will be j j j-j in the problem thus making the product 0. Hence the answer is 0 + j = j 0+j=j . But i don't think it's even a 1 level problem.

me too. I think this problem is overrated

Rajdeep Dhingra - 6 years, 7 months ago

Log in to reply

WHAT HAPPENED @Rajdeep Dhingra ?? Who is this @ef hg ? Your friend ?

Parth Bhardwaj - 6 years ago

Log in to reply

No he isn't. He just commented rudely that this problem is not overrated.

Rajdeep Dhingra - 6 years ago

Exactly. Way too overrated.

Mehul Arora - 6 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...