An algebra problem by Rahil Sehgal

Algebra Level 4

2 x + 1 1 + 2 x + 1 + 1 = 2 x + 1 \large |2^{x+1} -1| + |2^{x+1} +1| = 2^{|x+1|}

Find the integer value of x x satisfying the above equation.

Notation: |\cdot| denotes the absolute value function .


The answer is -2.

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1 solution

Guilherme Niedu
May 2, 2017

If x 1 x \geq - 1 :

2 x + 1 1 + 2 x + 1 + 1 = 2 x + 1 \large \displaystyle 2^{x+1}-1 + 2^{x+1}+1 = 2^{x+1}

2 x + 2 = 2 x + 1 \large \displaystyle 2^{x+2} = 2^{x+1}

x + 2 = x + 1 \large \displaystyle x+2 = x+1

Which has no solution. If x < 1 x<-1 :

1 2 x + 1 + 2 x + 1 + 1 = 2 x 1 \large \displaystyle 1- 2^{x+1} + 2^{x+1}+1 = 2^{-x-1}

2 = 2 x 1 \large \displaystyle 2 = 2^{-x-1}

1 = x 1 \large \displaystyle 1 = -x-1

x = 2 \color{#3D99F6} \boxed{\large \displaystyle x=-2}

Thank you sir.(+1)

Rahil Sehgal - 4 years, 1 month ago

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You're welcome :)

Guilherme Niedu - 4 years, 1 month ago

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