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Algebra Level 2

3 + log 2 x = log 2 5 3+ \log_2 x = \log_2 5 If the value of x x can be represented as p q \dfrac{p}{q} , where p p and q q are coprime positive integers, find p + q p+q .


The answer is 13.

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1 solution

Rishik Jain
Jan 5, 2016

log 2 5 log 2 x = 3 \log_2 5 - \log_2 x = 3

log 2 ( 5 x ) = 3 \log_{2}{\left( \dfrac{5}{x} \right)} = 3

2 3 = 8 \because 2^3 = 8

5 x = 8 \dfrac{5}{x} = 8

x = 5 8 x = \dfrac{5}{8}

5 5 and 8 8 are co-prime integers.

5 + 8 = 13 \therefore 5+8 = \boxed{13}

How did you came to 2nd line from 1st line??

Sagar Shah - 5 years, 5 months ago

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This is a property of Logarithms log a b log a c = log a ( b c ) \log_a b - \log_a c = \log_a{\left (\frac{b}{c} \right)}

Rishik Jain - 5 years, 5 months ago

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