A number theory problem by ritwik jain

True or False?

If a a and b b are positive integers such that a b + 1 ab + 1 divides a 2 + b 2 a^2 + b^2 then a 2 + b 2 a b + 1 \dfrac {a^2+b^2}{ab+1} is a perfect square.

False True

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1 solution

Tapas Mazumdar
May 17, 2017

Vieta root jumping is the best way to solve this problem. The solution has already been discussed here .

Even putting a = b = 1 a=b=1 will prove

Md Zuhair - 4 years ago

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Finding a specific case doesn't mean that the statement is always true. E.g. "If a a and b b are positive integers such that a + b a 2 b 2 a + b \mid a^2 - b^2 , then a b a-b is a perfect square. The statement is true for a = b = 1 a = b = 1 , but doesn't mean it is always true.

Calvin Lin Staff - 4 years ago

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Ok. Thank you sir

Md Zuhair - 4 years ago

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