Misconception??

Algebra Level 2

0.999... = ?? \large \lfloor 0.999... \rfloor = \text{ ??}

0 1

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1 solution

Zach Abueg
Aug 2, 2017

The misconception is that 0. 9 \color{#333333} 0.{\overline{9}} only approaches but does not equal 1 \color{#333333} 1 . Now, what do we mean when we say that two numbers are different? There must be at least one more real number between them (in fact, there are infinite).

Since

0. 9 = 0. 999 Infinite number of 9s \displaystyle \color{#333333} 0.{\overline{9}} = 0.{\underbrace{999 \ldots \ldots \ldots \ldots}_{\text{Infinite number of 9s}}}

there exists no number between 0. 9 \color{#333333} 0.{\overline{9}} and 1 1 , so it must be that they are the same. To show that 0. 9 = 1 \color{#333333} 0.{\overline{9}} = 1 , we have

x = 0.999 10 x = 9.999 10 x x = 9.999 0.999 9 x = 9 x = 1 \color{#333333} \displaystyle \begin{aligned} x & = 0.999 \ldots \\ 10x & = 9.999 \ldots \\ 10x - x & = 9.999 \ldots \ - \ 0.999 \ldots \\ 9x & = 9 \\ x & = 1 \ \ \blacksquare \end{aligned}

Isnt it 0 :P. I thought it. Because the integer part is 0

Md Zuhair - 3 years, 10 months ago

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Read this for more details.

Steven Jim - 3 years, 10 months ago

Great explanation!

Steven Jim - 3 years, 10 months ago

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