An algebra problem by rounak chatterjee

Algebra Level 3

For any two real numbers a a and b b , the operation \oplus defined by a b = a b + 1 a\oplus b=ab+1 is ____________________ . \text{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}.

neither commutative nor associative commutative and associative commutative but not associative associative but not commutative

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jaydee Lucero
Nov 5, 2014

a b = a b + 1 = b a + 1 = b a a \oplus b=ab+1=ba+1=b \oplus a Therefore, the operation is commutative . However, letting c c be a third real number, we have ( a b ) c = ( a b + 1 ) c = ( a b + 1 ) c + 1 = a b c + c + 1 (a \oplus b) \oplus c=(ab+1) \oplus c=(ab+1)c+1=abc+c+1 and a ( b c ) = a ( b c + 1 ) = a ( b c + 1 ) + 1 = a b c + a + 1 a \oplus (b \oplus c)=a \oplus (bc+1)=a(bc+1)+1=abc+a+1 The equality of the two above equations only holds if a = c a=c . Thus, for all real numbers a a , b b (and c c ), the operation is not associative .

Did exactly the same ! Well, I think no more method to check it, so all the solvers will do the same :P

Reeshabh Kumar Ranjan - 6 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...