A number theory problem by Sachin Vishwakarma

Let p p and q q be distinct primes. Find the number of positive integer solutions of the equation 1 x + 1 y = 1 p q \dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{pq} .


The answer is 9.

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1 solution

( x + y ) x y \frac{(x + y)}{xy} = 1 p q \frac{1}{pq}

or, (x + y)pq = xy

or, xy - (x + y)pq + p 2 q 2 p^{2}q^{2} = p 2 q 2 p^{2}q^{2}

or, (x - pq)(y - pq) = p 2 q 2 p^{2}q^{2}

So number of solutions = (2+1)(2+1) = 9

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