An algebra problem by Sahil Garg
There are two candles of equal lengths and of different thickness. The thicker one lasts of six hours. The thinner 2 hours less than the thicker one. Ramesh lights the two candles at the same time. When he went to bed he saw the thicker one is twice the length of the thinner one. How long ago (in hours) did Ramesh light the two candles.
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1 solution
After 3 hours height of small candle H/4 whereas heigt of big candle is 3H/6=h/2.