An algebra problem by Samriddhi Singha Roy

Algebra Level 2

Calculate the digit in the unit's place of the number 2! + 3! +...........99! .


The answer is 2.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Vaibhav Prasad
May 31, 2015

The answer to this problem is wrong

It must be 3 3

oh, yes. sorry. seems I had missed out 1!

Samriddhi Singha Roy - 6 years ago

Log in to reply

its allright

u can change the question to " give the answer-1 in the box"

Vaibhav Prasad - 6 years ago

Log in to reply

thanks. I think there should be an option of editing the answer also.

Samriddhi Singha Roy - 6 years ago

first calculate upto 2! , 3!, 4! , 5! , and 6! . from 5! onwards the last digit will be 0 . so we add till the last digit of 4! which is as follows: 2+6+4 = 12. so the last digit is 2.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...