An algebra problem by Shashank Shekhar Singh
Algebra
Level
pending
what will be the nth term T(n) for n \rightarrow \infty for the series...:
2, \frac {9}{4}, \frac {64}{27}, \frac {625}{256},.........................
The answer is 2.71818.
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1 solution
t(n)= [1+ \frac {1} {n}]^n
now lim n \rightarrow \infty t(n)= e=2.718