An algebra problem by shweta dalal
Algebra
Level
pending
There are red balls, blue balls and white balls in a box. The number of white balls is at least 1/3 of blue balls and does not exceed 1/4 of red balls. The sum of blue balls and white balls is at least 129. What is the minimum number of red balls?
The answer is 132.
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1 solution
Let red,blue and white balls are respectively denoted by R,B and W. Now we have W = B/3, or B = 3W, and W<= R/4. Also we have given B + W >= 129 or 3w + W >= 129 =>W>=33. So we have 33<=R/4 that implies 132<=R. Hence minimum number of red balls are 132.