Transitional Algebra

Algebra Level 2

( 16 3 3 3 ) 2 = ? (16 \sqrt[3]{3^3} ) ^ 2 = ?

2304 667 2486 3458 1568

Sina Asheghalishahi by Sina Asheghalishahi , 17, USA

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2 solutions

Mohammad Khaza
Jul 16, 2017

( ∛ ( 3 3 ) ) × 16 ( ∛(3^3))\ \times 16 = 3 × 16 3 \times 16 =48

now , 4 8 2 48^2 =2304

1 Helpful 0 Interesting 0 Brilliant 0 Confused

This problem can be solved by breaking it up, and first solving the cube root. 3 3 = 27 3^3=27 3 √ 27 = 3 • 3 • 3 = 27 , s o , 3 √ 27 = 3 3√27= 3•3•3=27, so, 3√27=3 Now that we know the cube root, we must solve everything in the parenthesis and then do the outer math: 16 • 3 = 48 , a n d , 4 8 2 = ∗ ∗ 2304 ∗ ∗ 16•3=48, and ,48^2= **2304**

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Are you asking for the value of ( 16 3 3 3 ) 2 (16 \sqrt[3]{3^3} ) ^ 2 ?

It was hard to read what you typed up.

Calvin Lin Staff - 4 years ago

Yes. very sorry.

Sina Asheghalishahi - 4 years ago

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Thanks. I have edited the problem for clarity.

As the problem creator, you can click on "Edit problem" in the menu to see how I typed in the LaTeX. Alternatively, you can click on "Toggle Latex" in the menu to have the equations displayed in LaTeX form.

Calvin Lin Staff - 4 years ago

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