A probability problem by Soham Choudhury
Probability
Level
pending
Find the probability of choosing a six digit number such that each succeeding digit is greater than the preceding one.
10P3
9C3
9P3
10C3
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1 solution
There are only 9 digits to choose from as 0 cannot be selected. Number of ways of doing this is 9C3. Now the selected numbers can be arranged in only 1 way so as to remain in ascending order. So number of six digit numbers satisfying given condition is 9C3x*1!=9C3