Horizontal Asymptotes

We know that the horizontal asymptote of a function $f(x)$ is the $\displaystyle\lim_{x\rightarrow \infty}f(x)$ . Therefore, the horizontal asymptote of the given function lies at:

$\displaystyle\lim_{x\rightarrow \infty}\dfrac{11x+2}{2x^3-1}=\displaystyle\lim_{x\rightarrow \infty}\dfrac{\dfrac{11}{x^2}+\dfrac{2}{x^3}}{2-\dfrac{1}{x^3}}\\=\dfrac{0+0}{2-0}=\boxed 0$