An algebra problem

$\large \displaystyle \frac{35x}{x+26} + 0.2 = 2.7 \implies \frac{35x}{x+26} = 2.5\\ \large \displaystyle \implies 35x = (x+26) \times 2.5 \implies 35x = 2.5x + 65.\\ \large \displaystyle \implies 32.5x = 65 \implies x = \frac{65}{32.5} = \color{#20A900}{\boxed2}$

$\huge Or$

$\large \displaystyle \frac{35x}{x+26} + 0.2 = 2.7. \text{ Multiply the equation with } (x+26)\\ \large \displaystyle 35x + 0.2 \times (x+26) = 2.7 \times (x+26) \implies 35x + 0.2x + 5.2 = 2.7x = 70.2\\ \large \displaystyle \implies 32.5x = 65 \implies x = \frac{65}{32.5} = \color{#D61F06}{\boxed2}.$

(35 * x) / (x + 26) + 0.2 = 2.7

=> 35x / (x + 26) = 2.5

=> 35x = 2.5x + 65

=> 32.5x = 65

=> x=2

The answer of this question is 2.

we could eliminate the .2 since at the end we will have a number .2 less then 2.7 which is 2.5 so we could divide 35 by 2.5 and get 14 so we know 14 x=x+26 then we could take away 1 x from each side and get 13 x=26 so divide 26 by 13

\dfrac { 35x}{x+26} + \color \red \dfrac{2}{10} = \color \red \dfrac {27}{10} $\implies \dfrac {35x}{x+26} = \dfrac{25}{10}$ $\implies 350x = 25x + 650$ $\implies 325x = 650 \implies x = \boxed {2}.$