An awsome puzzLe

Logic Level 2

Four friends A , B , C , D need to cross a bridge.
A maximum of 2 peoples can cross at a time.
It is night and they have just 1 lamp .
People that cross the bridge must carry the lamp to see the way.
A pair must walk together at the speed of slower person .

Speeds of
A : 1 minute to cross bridge.
B : 2 minutes to cross bridge.
C : 7 minutes to cross bridge.
D : 10 minutes to cross bridge.
What is the total minimum time (in minutes) required by all 4 friends to cross the bridge ?

18 12 10 17 21

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2 solutions

Akhil Bansal
Aug 6, 2015

First A and B will cross (2min).
Then A will return with lamp (1min).
Then C with D will cross (10min).
Then B will return with lamp (2min).
Then A with B again (2min).
Hence Total Time = 2+1+10+2+2 = 17 M i n u t e s \boxed{17 Minutes}

@Akhil Bansal But how do you prove that this is the lowest possible time??

Ankit Kumar Jain - 4 years, 2 months ago
Saya Suka
Apr 26, 2021

Answer
= ceiling[1,2] + 1 + ceiling[10,7] + 2 + ceiling[1,2]
= 2 + 1 + 10 + 2 + 2
= 17 minutes

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