An Easy Heron's Formula

We know the herons formula is $\sqrt{s(s-a)(s-b)(s-)}$

Here $\displaystyle s=\frac{17+25+26}{2} = 34$

$a=17, b=25, c=26$

Therefore the area of the triangle is,

$\sqrt{34(34-17)(34-25)(34-26)}$

Or, $\sqrt{(34)\times(17)\times(9)\times(8)}$

Or, $\sqrt{17\times2\times17\times3\times3\times2\times2\times2}$

Or, $\sqrt{204\times204}$

Or, $\boxed{204}$