Find minimum value of , if one root of equation is also a root of equation .
Note: and are natural numbers.
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Equation x²+2x+3=0. has D<0 , so both imaginary roots are common as imaginary roots appear in conjugate pair
When both roots are common then : (a/1) = (b/2) = (c/3)
By this : b=2a and c=3a
So a+2b+3c = a+4a+9a = 14a
Given : a is natural number , so lowest natural number =1 , so a=1
So minimum value of a+2b+3c=14