An easy sum?

At first we know $e=lim_{x \to \infty} (1+\frac{1}{x})^{x}$ . So we can make the expression be something like that, so we have. $lim_{x \to \infty} (1+\frac{3!}{x})^{x \cdot \frac{3!}{3!}}$ $= lim_{x \to \infty} ((1+\frac{3!}{x})^{\frac{x}{3!}})^{3!}$ $=e^6 = 403,42$

Use: $\lim_{x \to \infty }\left(\left(1+\frac{k}{x}\right)^x\right) = e^k$

$\LARGE \text{ADIOS!!!}$

We have

and

then after simplification :