Two trees A and B are on the same side of a river. From a point C in the river, the distances of trees A and B are 250 meters and 300 meters respectively. If angle C=45 degrees, find the distance between the trees (in meters, to 1 decimal place).
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Easily solved via the Law of Cosines:
A B 2 = A C 2 + B C 2 − 2 ( A C ) ( B C ) cos ∠ A C B = 2 5 0 2 + 3 0 0 2 − 2 ( 2 5 0 ) ( 3 0 0 ) cos ( π / 4 ) ;
or A B = 2 5 0 2 + 3 0 0 2 − 2 ( 2 5 0 ) ( 3 0 0 ) cos ( π / 4 ) ≈ 2 1 5 . 4 8 meters.