An easy Trigonometry problem of class-11

Geometry Level 3

Two trees A and B are on the same side of a river. From a point C in the river, the distances of trees A and B are 250 meters and 300 meters respectively. If angle C=45 degrees, find the distance between the trees (in meters, to 1 decimal place).


The answer is 215.5.

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1 solution

Tom Engelsman
Mar 27, 2021

Easily solved via the Law of Cosines:

A B 2 = A C 2 + B C 2 2 ( A C ) ( B C ) cos A C B = 25 0 2 + 30 0 2 2 ( 250 ) ( 300 ) cos ( π / 4 ) AB^{2} = AC^{2} + BC^{2} - 2(AC)(BC) \cos \angle{ACB} = 250^2 + 300^2 - 2(250)(300) \cos(\pi/4) ;

or A B = 25 0 2 + 30 0 2 2 ( 250 ) ( 300 ) cos ( π / 4 ) 215.48 AB = \sqrt{ 250^2 + 300^2 - 2(250)(300) \cos(\pi/4)} \approx \boxed{215.48} meters.

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