A copper wire has resistance 0.6 ohm.another copper wire of same mass as the first one is double the length of the first.find the resistance of second wire in ohms.
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SINCE THE VOLUME REMAINS SAME IN BOTH CASES. A * L = A' L' L' = 2L A' = A/2
R' = PL'/A' = 4PL/A = 4R 4 * .6 = 2.4 OHMS
FORMULA FOR THESE TYPE OF QUESTION = R' = N^2R WHERE N IS THE CHANGE IS THE CHANGE IN LENGTH.