An electricity and magnetism problem by vaibhav sinha
Electricity and Magnetism
Level
2
Three identical bulbs are connected in parallel with the battery.The current drawn from the battery is 6 A. If one of the bulbs gets fused what will be the total current drawn from the battery?
5 A
3 A
4 A
2 A
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1 solution
Let the potential difference maintained by the battery be V and let resistance of each bulb be R.If the equivalent resistance ofthe cicuit is r, r 1 = R 1 + R 1 + \frac{1}{R}\ or r=\(\frac{R}{3} The current is i= \frac{V}{r}=\(\frac{3V}{R} = R V =2 A 1 bulb is fused so r {1}= 2 R so current will be i {1}= \frac{V}{r_{1}}=\(\frac{2V}{R} =2*(2 A)=4 A