This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
We have ourselves an infinite geometric series with a 1st term of 1 and a common ratio of 1/3. The sum of an infinite geometric series is a/(1-r)=1/(1-1/3)=3/2. So we have log4(Y)=3/2. Y=4^(3/2)=8