An everyday situation for a retailer

Algebra Level 2

A mineral water bottle at a general store has a value of $2.20 in a certain currency. It is specified that the contents of the bottle along with the bottle together cost $2 more than the labeling and the service taxes on that bottle.

What is the total value of the contents of the bottle along with the bottle?


The answer is 2.10.

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1 solution

Tapas Mazumdar
Oct 14, 2016

Consider the value of 'labeling+service taxes' be x x . Then price of 'contents+bottle' is x + 2 x+2 .

Thus,

x + ( x + 2 ) = 2.20 2 x + 2 = 2.20 x + 1 = 1.10 Dividing both sides of the equation by 2 x = 0.10 x+(x+2)=2.20 \\ \implies 2x+2=2.20 \\ \implies x+1=1.10 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \small\color{#3D99F6}{\text{Dividing both sides of the equation by } 2} \\ \implies x=0.10

\therefore Price of 'contents+bottle' is x + 2 = 0.10 + 2 = 2.10 x+2 = 0.10+2 = \boxed{2.10} .


A common mistake that one makes in this problem is that we suspect that the answer is 2 2 for 'contents+bottle' and 0.20 0.20 for 'labeling+service taxes', but the difference between the values of the two, in this case, turns out to be 1.80 1.80 and not 2 2 .

Your English is too poor for this question to be clear

Kevin Weiss - 4 years, 8 months ago

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I'm sorry for that. Will put efforts to improve my vocabulary. Thanks for the feedback.

Tapas Mazumdar - 4 years, 8 months ago

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