An exponential Diophantine equation

Number Theory Level pending

How many positive integer solutions ( x , y ) (x, y) are there to the equation 5 x − 1 = y 2 5^x - 1 = y^2 ?


The answer is 1.

Star Fall by Star Fall , 29, Turkey

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1 solution

Sibe Bleuzé
Jun 16, 2016

5 0 − 1 = 0 2 5^0-1=0^2 and 5 1 − 1 = 2 2 5^1-1=2^2

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Are there any other solutions? If not, what is the proof?

Star Fall - 4 years, 12 months ago

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