An IIT level problem

Algebra Level 2


The answer is 1.

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1 solution

Genis Dude
Jul 7, 2017

ax^2 + bx + c = 0

Sum of roots of quadratic equation is -b/a

Product of roots of quadratic equation is c/a

Therefore, Sinθ + Cosθ = -b/a (eq1)

SinθCosθ =c/a (eq2)

(Sinθ + Cosθ)^2 = (-b/a)^2 (eq1)

(Sinθ)^2 + (Cosθ)^2 + 2SinθCosθ = b^2/a^2

1 + 2c/a = b^2/a^2

( (Sinθ)^2 + (Cosθ)^2=1) (SinθCosθ =c/a (eq2))

=a^2 + 2ac = b^2 (multiplying by a^2)

=a^2 + 2ac +c^2 = b^2 + a^2 (adding c^2 for completetion of square)

=(a+c)^2 = b^2 + c^2

Therefore, (a+c)^2/(b^2+c^2) = 1

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