A calculus problem by Guilherme Dela Corte

Calculus Level 2

Let f ( x ) = ( x 2 ) ( x 4 ) ( x 8 ) f(x) = (x-2)(x-4)(x-8) . Evaluate the digit sum of f ( f ( 16 ) ) f'(f(16)) .


The answer is 26.

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1 solution

f ( x ) = ( x 2 ) ( x 4 ) ( x 8 ) = x 3 14 x 2 + 56 x 64 f(x) = (x-2)(x-4)(x-8) = x^3 - 14x^2 +56 x - 64 f ( x ) = 3 x 2 28 x + 56 f'(x) = 3x^2 - 28x + 56 f ( 16 ) = 14 12 8 = 1344 f(16) = 14 \cdot 12 \cdot 8 = 1344 f ( 1344 ) = 1344 ( 3 1344 28 ) + 56 = 5381432 f'(1344) = 1344 \cdot (3 \cdot 1344 - 28) + 56 = 5381432 Σ = 5 + 3 + 8 + 1 + 4 + 3 + 2 Σ = 26. \Sigma = 5+3+8+1+4+3+2 \Rightarrow \boxed{\Sigma = 26.}

I did it!

Royette Posadas - 7 years, 1 month ago

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