A problem by Antony Diaz

We have a function that $f\left( 1 \right) =0\\ \\ f\left( 2n \right) =2\cdot f\left( n \right) +1\\ f\left( 2n+1 \right) =2\cdot f\left( n \right)$

What is the smallest n such that $\\ f\left( n \right) =2014\\ \\$ ?