Consider the numbers 9 , 9 9 , 9 9 9 , … , nine 9 ’s 9 9 9 9 9 9 9 9 9
The mean of these numbers is a 9-digit number, all of whose digits are distinct. This number does not contain what digit?
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nice solution......
T h a n k s .
The mean is 9 9 + 9 9 + 9 9 9 + ⋯ + 9 9 9 9 9 9 9 9 9 = 1 + 1 1 + 1 1 1 + ⋯ + 1 1 1 1 1 1 1 1 1 = 1 2 3 4 5 6 7 8 9 The missing digit is 0 .
one can easily get the answer without even adding the numbers
9 + 99 + 999........999999999
is same as
10 - 1 + 100 - 1 +........10^9 - 1
simplifying it
(10 + 100 +.....10^9) - (1*9)
Using GP series formula ( i.e. Sum = a(1-r^n)/1-r,
we get 10 + 100 + 1000......10^9 = 1111111110
= 1111111110 - 9 = 1111111101
For mean, Mean = 1111111101/9
which is 123456789
Therefore, we can get the answer without actually adding it easily. 0 is, therefore, the answer.
The most perfect answer. My vote up for you.......
But it is more tedious
the mean M = 9 9 + 9 9 + 9 9 9 + . . . . . + 9 9 9 9 9 9 9 9 9 = 1 + 1 1 + 1 1 1 + . . . . . . + 1 1 1 1 1 1 1 1 1 = 1 2 3 4 5 6 7 8 9
so the missing number is 0
أخيرا حد مصري بس جامد الحل بصراحة
common sense : a mean of this particular series cannot have a 0 , for example start with a smaller series [ which we can replicate into a larger series later , by induction] for a odd sequence 9,99,999 , mean is 369, similarly take even sequence, 9,99,999,9999... so a series ending in 9 nines [a odd sequence] also should not contain 0.
here, the mean can b written as.....
(9+99+999+9999+99999+999999+9999999+99999999+999999999)/9
= (1+11+111+1111+11111+111111+1111111+11111111+111111111)
=123456789
so here the missing digit is 0.
The mean of 9,99,999,............,999999999 will be same as (1+11+111+............+111111111) which is exactly equal to 123456789 and hence 0 is the missing digit.
The average of these numbers is (9 + 99 + 999 + 9999 + ... + 999999999) / 9. Distributing the division, we get 123456789, which does not have a 0.
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1 s t m e t h o d : This problem can be solved using simple arithmetic. We can add all the 9 numbers and then find their mean. Their sum = 9 + 9 9 + 9 9 9 + 9 9 9 9 + 9 9 9 9 9 + 9 9 9 9 9 9 + 9 9 9 9 9 9 9 + 9 9 9 9 9 9 9 9 + 9 9 9 9 9 9 9 9 9 = 1 1 1 1 1 1 1 1 0 1 The mean of these numbers = 9 1 1 1 1 1 1 1 1 0 1 = 1 2 3 4 5 6 7 8 9 Thus, the digit not present in the mean is 0 . 2 n d m e t h o d : The other method is simpler and logical. As all the numbers have only the number 9 as their digits, in order to find the mean we can simply divide each number by 9 and add them. So we get the mean as 9 9 + 9 9 9 + 9 9 9 9 + 9 9 9 9 9 + 9 9 9 9 9 9 + 9 9 9 9 9 9 9 + 9 9 9 9 9 9 9 9 + 9 9 9 9 9 9 9 9 9 + 9 9 9 9 9 9 9 9 9 9 = 1 + 1 1 + 1 1 1 + 1 1 1 1 + 1 1 1 1 1 + 1 1 1 1 1 1 + 1 1 1 1 1 1 1 + 1 1 1 1 1 1 1 1 + 1 1 1 1 1 1 1 1 1 = 1 2 3 4 5 6 7 8 9 So,the digit missing in the mean is 0 .