What's the missing digit?

Algebra Level 2

Consider the numbers 9 , 99 , 999 , , 999999999 nine 9 ’s 9,99,999, \ldots , \underbrace{999999999}_{ \text{nine} \space 9 \text{'s}}

The mean of these numbers is a 9-digit number, all of whose digits are distinct. This number does not contain what digit?


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

8 solutions

1 s t 1^{st} m e t h o d : method: This problem can be solved using simple arithmetic. We can add all the 9 9 numbers and then find their mean. Their sum = 9 + 99 + 999 + 9999 + 99999 + 999999 + 9999999 + 99999999 + 999999999 =9+99+999+9999+99999+999999+9999999+99999999+999999999 = 1111111101 =1111111101 The mean of these numbers = 1111111101 9 =\frac{1111111101}{9} = 123456789 =123456789 Thus, the digit not present in the mean is 0 \boxed{0} . 2 n d 2^{nd} m e t h o d : method: The other method is simpler and logical. As all the numbers have only the number 9 9 as their digits, in order to find the mean we can simply divide each number by 9 9 and add them. So we get the mean as 9 9 + 99 9 + 999 9 + 9999 9 + 99999 9 + 999999 9 + 9999999 9 + 99999999 9 + 999999999 9 \frac{9}{9}+\frac{99}{9}+\frac{999}{9}+\frac{9999}{9}+\frac{99999}{9}+\frac{999999}{9}+\frac{9999999}{9}+\frac{99999999}{9}+\frac{999999999}{9} = 1 + 11 + 111 + 1111 + 11111 + 111111 + 1111111 + 11111111 + 111111111 =1+11+111+1111+11111+111111+1111111+11111111+111111111 = 123456789 =123456789 So,the digit missing in the mean is 0 \boxed{0} .

nice solution......

Partho Kunda - 7 years, 5 months ago

T h a n k s . Thanks.

Soham Dibyachintan - 7 years, 5 months ago
Daniel Chiu
Dec 14, 2013

The mean is 9 + 99 + 999 + + 999999999 9 = 1 + 11 + 111 + + 111111111 = 123456789 \dfrac{9+99+999+\cdots+999999999}{9}=1+11+111+\cdots+111111111=123456789 The missing digit is 0 \boxed{0} .

Kartik Sharma
May 16, 2014

one can easily get the answer without even adding the numbers

9 + 99 + 999........999999999

is same as

10 - 1 + 100 - 1 +........10^9 - 1

simplifying it

(10 + 100 +.....10^9) - (1*9)

Using GP series formula ( i.e. Sum = a(1-r^n)/1-r,

we get 10 + 100 + 1000......10^9 = 1111111110

= 1111111110 - 9 = 1111111101

For mean, Mean = 1111111101/9

which is 123456789

Therefore, we can get the answer without actually adding it easily. 0 is, therefore, the answer.

The most perfect answer. My vote up for you.......

Nishant Sharma - 7 years ago

But it is more tedious

Magnas Bera - 1 year, 11 months ago
Mohamed Mahmoud
Dec 14, 2013

the mean M = 9 + 99 + 999 + . . . . . + 999999999 9 = 1 + 11 + 111 + . . . . . . + 111111111 = 123456789 M=\frac{9+99+999+.....+999999999}{9}=1+11+111+......+111111111=123456789

so the missing number is 0 \boxed{0}

أخيرا حد مصري بس جامد الحل بصراحة

عمرو إبراهيم - 7 years, 6 months ago
Aritri Chatterjee
Feb 10, 2014

common sense : a mean of this particular series cannot have a 0 , for example start with a smaller series [ which we can replicate into a larger series later , by induction] for a odd sequence 9,99,999 , mean is 369, similarly take even sequence, 9,99,999,9999... so a series ending in 9 nines [a odd sequence] also should not contain 0.

Nurul Alam Pavel
Dec 15, 2013

here, the mean can b written as.....

(9+99+999+9999+99999+999999+9999999+99999999+999999999)/9

= (1+11+111+1111+11111+111111+1111111+11111111+111111111)

=123456789

so here the missing digit is 0.

Sharan Girdhani
Dec 15, 2013

The mean of 9,99,999,............,999999999 will be same as (1+11+111+............+111111111) which is exactly equal to 123456789 and hence 0 is the missing digit.

Edward He
Dec 14, 2013

The average of these numbers is (9 + 99 + 999 + 9999 + ... + 999999999) / 9. Distributing the division, we get 123456789, which does not have a 0.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...