A problem by Vishal Choudhary
An unbiased die, with faces numbered 1, 2, 3, 4, 5, and 6, is thrown five times and list of the five numbers showing up is noted then the probability that among the numbers 1, 2, 3, 4, 5, and 6 exactly 4 numbers appear in the list can be given as a/b. The value of a+b is
The answer is 79.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
0 solutions
No explanations have been posted yet. Check back later!