Trace The Nested "For" Loops

The answer is $0$ because the indentation is faulty. But assuming the correct indentation, we note that we encounter $3$ values of $i$ and $5$ values of $j$ , so the answer is $3 \cdot 5 = \boxed {15}$ .

"for i in range(2, 5)" means $i\in[2, 4]$ and it is an integer. Therefore, there are $4-2+1=3$ possibilities for $i$ . "for j in range(4, 9)" means $j\in[4, 8]$ and it is an integer. Thus, there are $8-4+1=5$ possibilities for $j$ . Therefore, $print(1, j)$ is executed $3\cdot5=\boxed{3) 15}$

This is an example of nested loops where i is counter of outer loop and j is counter of inner loop. The outer loop runs 3 times with i=2,3,4 and corresponding to each execution of outer loop, the inner loop gets executed 5 times with j=4,5,6,7,8. print(i,j) is within the inner loop. So, total no. of times print(i,j) gets executed $=(3\times 5) = \boxed{15}$

Answer: 3) 15.

For 'i' in range (2,5) means that the loop will run if 'i' is 2, 3, or 4. Hence, 3 times. Now, the second loop will run 5 times as the value of 'j' should be in the range of (4,9) that is, 4, 5, 6, 7 or 8.

Now the nested loop [for j in range(4,9)] will run 5 times in each of the three instances of the first loop [for i in range(2,5)]. Ergo, resulting in total 5*3 = 15 executions of print(i,j)

$range(2, 5)$ iterates 3 values: 2, 3, and 4

$range(4, 9)$ iterates 5 values: 4, 5, 6, 7, and 8

Therefore there are $3 \times 5 = 15$ combinations of $i$ and $j$

for i it takes 3 num and for j it takes 5 num so 5*3=15

I have no idea about python language . But when i tried to compile the code given on the problem statement , following warning showed up : 'IndentationError: expected an indented block (<string>, line 2) ' . I didn't hear anything like 'IndentationError:' in c or cpp language .

c=0 for i in range(2, 5): for j in range(4, 9): c=c+1 print c

in the above python code the value of c gives the answer..

Its So Simple Actually It should be told that the python includes the range values or excludes it, here situaltion is bit differnet a range in python works like this as (4,9) means 4 is inclusive while 9 exclusive :) so it will iterate 4,5,6,7,8

in range(a,b) :iteration takes place from a(included) to b(not included)..

Python will read set formed by $(2,3,4) \times (4,5,6,7,8)$

The answer $3 \times 5=\fbox{15}$

Write the script for a python compiler and declare a variable 'counter' at first. write 'counter = counter + 1' below 'print (i, j)' and write 'print counter' in the script's end.

This is actually more of a counting problem. Once inside the first for- loop, we see that the program will iterate over $3$ objects (due to syntax: $2, 3, 4$ ). For each of the objects we go on to the next step and see that the for- loop at this level is iterated over $5$ times ( $4, 5, 6, 7, 8$ ) executing the print statement for each object. Thus the print statement will be executed $3*5 = \boxed{15}$ times.