A problem by Jordi Bosch
The complex number z = lies above the bisection of the second quadrant.
The value of x can be written as What is ?
The answer is 23.
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1 solution
I shared this problem, so I think I should post my solution.
First of all, let's see what number is z .
z = 4 − 3 i 3 − 2 x i → ( 4 − 3 i ) ( 4 + 3 i ) ( 3 − 2 x i ) ( 4 + 3 i ) → 2 5 ( 1 2 + 6 x ) + ( 9 − 8 x ) i
The bisection of the second quadrant holds y = − x , so the two coordinates must be equal with signs changed.
2 5 1 2 + 6 x = − 2 5 9 − 8 x → 1 2 + 6 x = − 9 + 8 x → 2 x = 2 1 → x = 2 2 1 → x = 2 3