A problem by Kamran Anjum

Kamran, you can use [LaTeX](http://tny.cz/1f2b40b9 to make your problem look a little more "beautiful".

Let $x$ and $y$ be real numbers such that $(x+y)=58$ and $(x-y)=46$ . What is the value of $xy$ ?

SOLUTION: By summing the two initial equations, we get $2x = 104 \Rightarrow x = 52$ . Plugging $x$ back to any equation will lead us to $y = 6$ .

Thus, $xy = 52 \times 6 = \boxed{312.}$

SUGGESTION :

Try developing harder / more interesting problems when submitting to Brilliant.

A idea I'd give you is:

Let $x$ and $y$ be real numbers such that $(x+y^2)=52$ and $(x^2+y)=16$ . What is the value of $xy$ ?