Triangle ABC is right-angled about B and AC=12. X is the foot of perpendicular from B to AC such that Find the length of BC.
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Assume BC = x, CX = y.. So AX = y^2. y^2 + y = AX + XC = AC = 12, y^2 + y - 12 = 0, (y + 4)(y - 3) = 0, y = 3. From similarity of triangles AXB, BXC we have BX^2 = AX.XC = y^3. From similarity of triangles BXC, ABC we have x^2 = BC^2 = AC.CX = 12y = 36. Hence BC = x = 6.