6 6 5 4 3 2 1 a + 7 5 5 4 3 2 1 b + 7 6 4 4 3 2 1 c + 7 6 5 3 3 2 1 d + 7 6 5 4 2 2 1 e + 7 6 5 4 3 1 1 f + 7 6 5 4 3 2 0 g = 2 9 6 7 5 4 6 2 4
Determine the sum of the elements of all possible tuples ( a , b , c , d , e , f , g ) of positive integers less than 10 that satisfy the equation above.
Note that the integers do not necessarily have to be distinct.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Add a 7-digit number a b c d e f g to both the sides and re-write the given equation as 7 6 5 4 3 2 1 ( a + b + c + d + e + f + g ) = 2 9 6 7 5 4 6 2 4 + a b c d e f g . Simple calculation that gives the next multiple 7 6 5 4 3 2 1 ( 1 + 7 + 6 + 3 + 8 + 9 + 5 ) = 2 9 6 7 5 4 6 2 4 + 1 7 6 3 8 9 5 . Sum of digits is 39.
I like your solution, but I think you should point out why you added [ ˉ a b c d e f g ] with a step showing each coefficient being 7 6 5 4 3 2 1 − 1 0 n . This will explain why you added [ ˉ a b c d e f g ] to the viewers.
Problem Loading...
Note Loading...
Set Loading...
6 6 5 4 3 2 1 a + 7 5 5 4 3 2 1 b + 7 6 4 4 3 2 1 c + 7 6 5 3 3 2 1 d + 7 6 5 4 2 2 1 e + 7 6 5 4 3 1 1 f + 7 6 5 4 3 2 0 g = = 7 6 5 4 3 2 1 ( a + b + c + d + e + f + g ) − ( 1 0 0 0 0 0 0 a + 1 0 0 0 0 0 b + 1 0 0 0 0 c + 1 0 0 0 d + 1 0 0 e + 1 0 f + g ) = = 2 9 6 7 5 4 6 2 4 ⇒ 7 6 5 4 3 2 1 ( a + b + c + d + e + f + g ) − 2 9 6 7 5 4 6 2 4 = = ( 1 0 0 0 0 0 0 a + 1 0 0 0 0 0 b + 1 0 0 0 0 c + 1 0 0 0 d + 1 0 0 e + 1 0 f + g ) ← this is a 7-digit number a b c d e f g ⩾ 1 1 1 1 1 1 1 . 7 6 5 4 3 2 1 ⋅ 3 8 < 2 9 6 7 5 4 6 2 4 and 7 6 5 4 3 2 1 ⋅ 4 1 − 2 9 6 7 5 4 6 2 4 = 1 7 0 7 2 5 3 7 has more than 7 digits, so a + b + c + d + e + f + g = 3 9 and ( a , b , c , d , e , f , g ) = ( 1 , 7 , 6 , 3 , 8 , 9 , 5 ) (because 7 6 5 4 3 2 1 ⋅ 3 9 − 2 9 6 7 5 4 6 2 4 = 1 7 6 3 8 9 5 or a + b + c + d + e + f + g = 4 0 and ( a , b , c , d , e , f , g ) = ( 9 , 4 , 1 , 8 , 2 , 1 , 6 ) (because 7 6 5 4 3 2 1 ⋅ 4 0 − 2 9 6 7 5 4 6 2 4 = 9 4 1 8 2 1 6 . The first option is correct, while the second is contradictory, hence the answer is 39 .