How many positive integers satisfy the following inequality?
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2 n ≤ 2 n − 1 6 n
n ≤ n − 1 6 n
Because n > 0
1 ≤ n − 1 6
Also n − 1 > 0
n − 1 ≤ 6
n ≤ 7 To make sense of the denominator , n = 1
n = 2 , 3 , 4 , 5 , 6 , 7