An unlucky problem?

The year 2017 began with a Friday the 13th in January, and another one is due in October. What’s the maximum and minimum number of Friday the 13th’s that there can be in a Gregorian calendar year? Let the maximum number of Friday the 13th’s be M M and minimum number of Friday the 13th’s be S S . Submit your answer as M + S . M+S.


The answer is 4.

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