What is the angle (in degrees) produced between the little hand (hours) and big hand (minutes) when the time is 2:15 PM?
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Sorry but could please explain in a bit more detail
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You should explain the 3 0 ∘ part for clarity.
But the question doesn't give u any information about the stsrting point which means it's just 30 degrees
In the analog watch, create 360 degree in the center and analog watch is divided into 12 same arc(Hours).
So difference between one hours to next hours is = 360/12=30 degree. That's means, angle between hours 2 to 3 is 30 degree.
But, as Second hand is on the 15 minutes. So, hand of hour is slightly fall from 2.
As, Hours hand is move 30 degree when Minutes Hand is move 360 degree. So after move Minutes hand as 90 degree(12 to 3) then Hours hand will be move=(30x60)/360 = 7.5 degree. So the falling angle of Hours hand is 7.5 degree.
So. the Angle between Hours and Minutes hand is= 30-7.5 = 22.5 degree.
I'm not that good at math but... Isn't (30x60)/360= 1800/360=5 ??? I mean I haven't read what you wrote I just came and read the answer. I got the answer 24, I didn't do a lot of math, I just thought it was obvious.
In 1 hour, hour hand traverses 30 deg. , In 15 mins, hour hand will therefore traverse 30/4 =7.5 deg.
Angle between 2 and 3 of hour hand = 360/12= 30 deg .. Therefore answer=30 – 7.5= 22.5 degrees...
2.5 degrees because it is not a full 30 degrees due to the constant motion of the smaller hand. The small hand should be 1/4 through between '2' and '3' at 2:15.
You assume it is the smallest angle that is required! If so solutions are correct, but whaty is it if the solution required is the larger. Reword the question correctly.
I thought of it like this: 90 degrees = 15 min. 15/5=3. And like every 5 min is 30 degrees. But the little hand were pointing at one less. so 30/5 = 6. every 1 min = 6 degrees. The little hand was pointing at 4 mins which is 24 degrees... HELP ME PLS I NEED TO UNDERSTAND IT! And thank you.
ø = 11/2 m – 30 h where ø = angle between 2 hands of a clock. h = hours completed. m = minutes completed.
here h = 2 hr, m = 15 minutes. substituting in the formula,
ø = 11/2 × 15 – 30 × 2
= 82.5 – 60 = 22.5
Angle between 2and 3 is 360/12=30.Hour needle has moved 1/4 th of an Hour it has moved by 7.5 degree.30-7.5 is 22.5 degree.
30-(30 x 1/4) =(30 x 1) - ( 30 x 1/4 ) = 30 x ( 1-1/4 ) = 30 x 3/4 = 22,5
I hour= 30 degree 1 hour= 5 subdivision when minute hand moves by 15 minutes the hour hand moves by 1.25 subdivision So if 5 subdivision corresponds to 30 degrees (5-1.25) subdivision corresponds to how much degree? 3.75*30/5 =22.5
A full rotation of the short hand is 12 hours and it is at 2:15 (or 2,25) of its course so: 2,25 / 12 * 360° = 67,5°
Long hand is at 90° so the difference is 90° - 67,5° = 22,5°
we can use a simple rule : (number of hours *30) - (11/2 * number of minutes ) note that 1 o'clock = 13 hours , 2 o'clock = 14 hours .. So , by applying this rule we find that : (14 *30 ) - (11/2 * 15) = 420 - 82.5 = 337.5 (which is the big angle) the small angle : 360 - 337.5 = 22.5
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In 15 minutes the minute hand went: 1 5 × 6 0 3 6 0 ° = 9 0 ° In 15 minutes the hour hand went: ( from 2 o'clock) 1 5 × 6 0 3 0 ° = 7 . 5 ° In 2 hours the hour hand went: 6 3 6 0 ° × 2 = 6 0 ° Therefore the angle produced is: 9 0 ° − 7 . 5 ° − 6 0 ° = 2 2 . 5 °