Analogy

Algebra Level pending

$\begin{cases} 2x^2 + 13x + 21 = 0 \\ 3y^2 + 34y + 63 = 0 \end{cases}$ Find the relationship between $x$ and $y$ .

x > y

Relationship between

x

and

y

can’t be established.

x \le y

x \ge y

x < y

1 solution

Ravneet Singh
May 24, 2017

On solving $2x^2 + 13x + 21 = 0$ , we get $x = \dfrac{7}{2}$ and $x = -3$

and on solving $3y^2 + 34y + 63 = 0$ , we get $y = \dfrac{-7}{3}$ and $y = -9$

since $\dfrac{7}{2} >\dfrac{-7}{3} \implies x > y$

but $-3 < \dfrac{-7}{3} \implies x< y$

therefore relationship cannot be established.