Analytical Chemistry (Mixing)

We have 2 litre $\ce{NaOH}$ 1.5N we need to raise the concentration to become 3.6N by adding a known volume from stock solution whose concentration is 5.2N

Then we need to convert all $\ce{NaOH}$ in the resulting solution (whose concentration is 3.6 and it's volume is unknown) into $\ce{NaCl}$ by adding $\ce{HCl}$ 37% w/w and it's specific gravity is 1.19 gm/ml and it's molecular weight is 36.46 so calculate the exact volume of $\ce{HCl}$ needed without any excess.

Write the volume in litres to the nearest one decimal.