If the area of square ABCD is 25 square units , then the area of the larger square is
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Let the radius of the circle be r units and side of bigger square be x units.AB = AD = 5 .OP = OC = radius = r . From Pythagoras theorem , r^2 = x^2 +(x/2)^2 r^2 = 5^2 + (5+x/2)^2 .Solving the two equations , we get x= 10 (since negative value lapses). And we are done!