And they're off!

From the given, we can get that $d=100m$ , $t=5s$ , and $v_{i}=0m/s$ .Using the fundamental kinematic equation $d=v_{i}t+\frac{1}{2}at^{2}$ , we get $100m=(0m/s)(5s)+\frac{1}{2}(a)(5s)^{2}$ . Solving for a, we get $8m/s^{2}$

Kinematic equation: d = v.t + 1/2.a.t^2

Solve for a: a = 2d / t^2

Plug things in: a = 2.100 / 5^2

Simplify: a = 200 / 25

Solve: a = 8 m / s^2

acceleration = 2 (distance - initial velocity)/time squared

a = 2 (100-0)/25

a = 200/25

a = 8

s=ut+0.5a $t^{2}$ ......100=12.5a........a=8

Sim l u y + 1 ^use the kinematic equation:-.

S =.Ut +1/2At^2 . Here u is initial velocity which is zero here, S is total distance covered a, t is time and A is acceleration..............solve the eqn and u get answer